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X^2-5.3X-4=0
a = 1; b = -5.3; c = -4;
Δ = b2-4ac
Δ = -5.32-4·1·(-4)
Δ = 44.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.3)-\sqrt{44.09}}{2*1}=\frac{5.3-\sqrt{44.09}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.3)+\sqrt{44.09}}{2*1}=\frac{5.3+\sqrt{44.09}}{2} $
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